- a) - The given data is as follows,  - Comment 
- Step 2 of 7- The saturation or mm polot between [S] and [v] is as folows,  - The plot of v versus S indicates that it as a  reaction. As the action of enzyme got inhibited with the increase in the concentration of the substrate. reaction. As the action of enzyme got inhibited with the increase in the concentration of the substrate.- Comment 
- Step 3 of 7- b) - Determining the constants  : To determine : To determine , , and and are are plotted to obtain a Line-WeaverBurk plot, as given below: are are plotted to obtain a Line-WeaverBurk plot, as given below: - Comment 
- Step 4 of 7 and and are determined from low substrate concentration, where inhibition is not effective. are determined from low substrate concentration, where inhibition is not effective. - From the obtained LB plot the line of equation is  . .- Calculation of  is as follows, is as follows,  - Thus, the  - Comments (4) 
- Step 5 of 7- The calculation of  is as follows, is as follows, - Thus, the  - Comments (3) 
- Step 6 of 7- Determining  from maximum reaction rate: which can be determined by setting , from maximum reaction rate: which can be determined by setting , - From plot,  90 mg/l 90 mg/l - Therefore,  - Comments (1) 
- Step 7 of 7- c) - Rate of reaction at [S] = 70 mg/l, Since inhibition effect is not observed at this substrate, the equation 3.35 must be used  - Therefore, the oxidation rate at [S] = 70 mg/l is  - Comment 
