- ahmad alhayek
الرئيسية صورة وعبرة كلام الناس خواطر

 

Problem

In free space, let D = 8xyz4ax+4x2z4ay+16x2yz3az pC/ m2. (a) Find the total electric flux passing through the rectangular surface z = 2, 0 < x < 2, 1 < y < 3, in the az direction. (b) Find E at P(2,−1, 3). (c) Find an approximate value for the total charge contained in an incremental sphere located at P(2,−1, 3) and having a volume of 10−12 m3.

Step-by-step solution

  1. Step 1 of 5

    a)

    Calculate the value of total electric flux passing though the rectangular surface.

    Thus, the value of total electric flux passing though the rectangular surface is.

  2. Step 2 of 5

    b)

    Calculate the value of electric field.

    Thus, the value of electric field  is.

  3. Step 3 of 5

    c)

    Calculate the value of.

  4. Step 4 of 5

    Calculate the value of.

    Calculate the value of.

  5. Step 5 of 5

    Calculate the value of charge enclosed in volume.

    Thus, the value of charge enclosed in volume is.

At point P(-3, -4, 5), express the vector that extends from P to Q(2, 0, -1) in: (a) rectangular coordinates (b) cylindrical
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Expert Answerinformation icon

  • Vamsi Krishna's Avatar
    Vamsi Krishna answered this
    629 answers

    Given p (-3,-4,5) Q (2,0,-1) @ Rectangular co-ordinates let (x, 4, 2,) = (-3,-4,5) (2 Y₂ Z₂): (2 ol 0,-) PQ = (x2-x1) ? +(Yz-In cylindrical co-ordinates (ridiz) r= (x²+y2 Here 20 : 5 8= √5²+42 2 2 = -6 from eq tano = YG = O. tant(els) : 0 - 11-3° z =by 2. © In spherical co-ordinates (8,0.9) are green Gris Jx² + y² +2² y=4 tañ (x) = co cost from rectangular co-ordinates z

    Comment 

  • D2.6. Three infinite uniform sheets of charge are located in free space as follows: 3 nC/m² at z = -4, 6 nC/m² at z = 1, and
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    • revati's Avatar
      revati answered this
      1,747 answers

      Answes a) Given PA (2,5,-5) So B = 3x10/9 X 3671 (-22) + 6x10 x 36IT (-az). 2x104 8x10 x 367a axit So e = 180 (-a2) di È = -518 SET (22) X10 Exio X exista d) Pp (-2,4,5) ² = 8x107 x 36 IT (-a2) 6x109 x 367 (0:2) 3x104 8x69 So ² = -luuntaz + 108taz +5

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