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  Anonymous answered this

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  Step 1: Code

  .data
  myMsg BYTE "Enter a number to be evaluated:",0dh,0ah,0
  factor DWORD 2
  hold DWORD ?
  .code
  main PROC
  call Clrscr

  mov edx,offset myMsg
  call WriteString ;Displays myMsg
  call ReadDec ;Puts the value into EAX register
  mov edi, factor
  call prime

  
  exit
  main ENDP

  prime PROC

  step1: mov hold, eax
  mov eax, hold
  xor edx, edx
  div edi
  cmp edx, 0
  je step2
  add factor, 1
  mov edi, factor
  jmp step1

  step2: mov hold, eax
  mov eax, edi
  call WriteDec
  mov eax, hold
  CMP eax, 1
  jz step3
  jmp step1

  step3:
  exit
  prime ENDP

  
  END main

  Step 2: Summary

  I hope this code help you. Thank you.

  Comment 

Show transcribed image text

Expert Answer

• 
  Koushal Kumar answered this

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  9 answers

  .model small
  .stack 100h
  .data
  num db ?
  msg db 'Multiplication table of :$'
  string db 5 dup(?)
  .code
  main proc
  MOV AX, @data
  MOV DS, AX

  LEA DX, msg ;; PRINT THE INPUT NUMBER
  MOV AH, 9
  int 21h
  MOV AH, 1
  int 21h
  SUB AL, 48 ;; CONVERTING INTO NUMBER
  MOV num, AL

  XOR BX, BX
  MOV BL, 1
  MOV CX, 10
  TOP:MOV AL, num   
  MUL BL
  PUSH BX   
  PUSH CX
  LEA SI, string

  MOV BX, 10
  XOR CX, CX
  DIVISION: XOR DX,DX
  DIV BX
  PUSH DX
  INC CX
  CMP AX, 0
  JNE DIVISION
  STORE: POP DX
  ADD DL, 48
  MOV [SI], DL
  INC SI
  LOOP STORE
  MOV [SI], '$ '

  POP CX
  POP BX
  MOV DL, 13   
  MOV AH, 2
  INT 21h
  MOV DL, 10
  MOV AH, 2
  INT 21h
    
  LEA DX, STRING   
  MOV AH, 9
  INT 21h

  INC BL
  LOOP TOP   

  MOV AH, 4ch ;; END
  INT 21h
  MAIN ENDP
  END
  

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